The four corner pixels are
(x,y) = (0,0) - the top left pixel
(x,y) = (224,0) - top right
(x,y) = (0,224) - bottom left
(x,y) = (224,224) - bottom right
So, to pick out the 5th character from the left in the 3rd row from the top, the "8", you need something like the following which assumes the character occupies a block of 22x22 pixels:
load bitmap "image.bmp", 1
row = 3
column = 5
rowOffset = 1 ` the two offsets look as if they differ for each character
columnOffset = 4
get image 1, (column-1)*22 + columnOffset, (row-1)*22 + rowOffset, column*22 + columnOffset - 1, row*22 + rowOffset - 1, 1
save image "char8.png", 1
However, it's your image so only you will know how the characters are laid out - if it's not your image then neither you nor I will know and you can find the four corners of each character as well as I or anyone else. The simple fact that 225 is not a multiple of 10 is a complicating factor and a quick glance suggests each character is about 22x22 pixels in size.