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Dark GDK / dbLimbName

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Benjames8
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Posted: 5th Oct 2010 06:39 Edited at: 5th Oct 2010 08:00
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This probably a noob question..

if(dbLimbName(obj,limb)=="Chest"){print "something";}

It doesn't print. So pretty much I'm having troubles comparing limbname's.

In dbpro:
if limb name(obj,limb) = "Head" ; print "yourmom"; endif
totally works

my actual code is this :


[off subject] Anyone know a way to change a single face in code? like it's color or texure. Can you give an example? Can this be done by using code from augest 2007 directx sdk?
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Hassan
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Posted: 5th Oct 2010 15:16 Edited at: 5th Oct 2010 15:17
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you can'y compare strings to strings using '==', use strcmp instead

also note that strcmp returns ZERO if it succeeds, dunno why they made it like that, sounds dumb, but well that's it

@ your second question, what do you mean? character face?

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Benjames8
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Posted: 5th Oct 2010 16:19
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Is strcmp part of string.h? Should it look like this?

if(strcmp(dbLimbName(obj,limb),"Head")==0){something;}

The second question is on mesh face's, I was looking around in the direct "x files" and found STDMETHOD(SetFaceAttribute)(UINT iFace,DWORD Attribute) PURE; there where some comments about how you can set an id to a face and change it's material.
I don't know where to even start with this, so maybe it is too much for me but I am up for giving it a shot if someone wants to point me in a good direction

Thanks BTW Hassen
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Hassan
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Posted: 5th Oct 2010 17:35 Edited at: 5th Oct 2010 19:26
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Yes i believe that's how it's done, but i think you need to free the pointer returned by dbLimbName, e.g.


the attribute is used for subsets, it has nothing to do with materials

the object has a vertex buffer and an index buffer, and optionally an attribute buffer, vertex buffer includes vertex data (position color uvs etc), index buffer describes how vertices are bound together to form triangles, the buffer is either a DWORD array or WORD, it's size is 3 * number of triangles, 3 indices for every triangle, now the attribute buffer contains info about faces, so face 0 for example (which is indices[0], indices[1] and indices[2]) might hold the value of 0 in the attribute buffer stating that the face 0 is in subset 0

it's far from anything to do with materials, what do you want to do anyway?



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Dodga
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Posted: 5th Oct 2010 19:14
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Try this:

std::string str4;
std::string name2="Chest";
size_t found2;

for (int xxx2=1; xxx2<10; xxx2++)
{
for(int limbsint7=0; limbsint7<500;limbsint7++)
{
if(dbLimbExist(5,limbsint7)==1 )
{

str4=dbLimbName(5, limbsint7);
found2=str4.find(name2);
if(found2!=std::string::npos)
{

Code here


}

}
//}
}
}
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Mireben
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Posted: 6th Oct 2010 20:44
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Quote: "i think you need to free the pointer returned by dbLimbName,"


Yes but use delete[] instead of delete.

The problem with assigning the returned value to an std::string directly is that the returned pointer cannot be deleted. Store the pointer and then it can still be assigned to a string.
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Benjames8
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Posted: 13th Oct 2010 08:30
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Are you saying dbLimbName(x,xx); makes somthing like a a variable and i need to delete it? Like it is in a funtion, I thought all variable's are free'd after the funtion returns to main, or maybe right before?

Quote: "it's far from anything to do with materials, what do you want to do anyway?
"


Idk something that look's sweet, lol changed in real-time.
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Hassan
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Posted: 13th Oct 2010 15:22
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it allocates new memory for the returned buffer on the heap (using new operator), so you must free it yourself

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Hawkblood
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Posted: 13th Oct 2010 17:48
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@ Hassan,
Quote: "also note that strcmp returns ZERO if it succeeds, dunno why they made it like that, sounds dumb, but well that's it"

That's because strcmp() will give a lexicographical orientation of the strings in question. A negative value means the first string is, in "alphabetical" order before the second string and a positive means it's after. (I may have those reversed but you get the idea). And of course, a 0 means they are the same.

The fastest code is the code never written.
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