I've spent a bit of time and frustration trying to figure this out. Only to realize I was looking for SinRad() not Sin().
So I thought I would share it with everyone. Example attached!
// Give this a Linear value and it will return an Interpolated value.
FUNCTION EaseInEaseOut(LinearPos#,StartPos#,EndPos#)
Distance# = EndPos#-StartPos#
NormalizeToHalfPi# = ((LinearPos#-StartPos#)/Distance#*2-1)*(1.570796)
y# = SinRad(NormalizeToHalfPi#)
InterpPos# = (y#*Distance#/2)+(StartPos#+Distance#/2)
ENDFUNCTION InterpPos#
