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AppGameKit Classic Chat / [SOLVED] Best way of figuring out the length of an array that is multidimensional ????

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PHeMoX
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Posted: 20th Nov 2018 12:33
Heey everyone!

To all you coding gurus out there; is there a way of quickly figuring out an arrays length? I'm trying to implement a level saving / loading functionality and am wondering if I need to use a separate array to just store the lengths of multidimensional arrays and restore the level from there. I am intending to use the built-in functionality of saving arrays and JSONs. Can I read the lengths from those somehow?

In terms of code, I'm setting a random map size for the X axis and Y axis, then use a MAP[size_x,size_y] array to fill it up with objects. I can restore the placed tiles just by reading their x,y,z locations which I save also, however the MAP[a,b] array is used for pathfinding / player seeking and some behaviours, so it shouldn't be empty. Same goes for arrays that save enemy positions for example.

Anyway, some tips are greatly appreciated

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puzzler2018
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Posted: 20th Nov 2018 12:59 Edited at: 20th Nov 2018 13:00
Yes - an array length can be achieved by putting .Length on the end



Im not sure about multidimension arrays though not without testing but I think It works too in the same way

Others here will be able to correct you on this if that's not the case
PHeMoX
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Posted: 20th Nov 2018 13:45
Yeah, the .length seems to return only the length of the first dimension, or at least I wouldn't know the correct syntax for the other dimension otherwise.
In your example, how would you deduce / extract the Size_Y without manually storing that value yourself?


Jack
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Posted: 20th Nov 2018 13:48 Edited at: 20th Nov 2018 13:52
This post has been marked by the post author as the answer.
try:
arr.length = x
arr[0].length = y
arr[0,0].length = z
....

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PHeMoX
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Posted: 20th Nov 2018 13:52 Edited at: 20th Nov 2018 13:53
edit: Ahhhh nevermind my comment below, thank you Jack that's exactly what I'm looking for!!

I think I have just found it :


Not sure if the [0] can be set to any higher dimension, it will return whatever length the second dimension in the array is even with say map[30].length
It doesn't seem to be in the manual though!!!
PHeMoX
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Posted: 20th Nov 2018 14:01 Edited at: 20th Nov 2018 14:17
Quote: "
try:
arr.length = x
arr[0].length = y
arr[0,0].length = z
"


So I guess we can also do something like this then??

arr.find(x)
arr[0].find(y)
arr[0,0].find(z)

edit: fixed syntax

That actually would solve some other things as well.
PHeMoX
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Posted: 20th Nov 2018 14:21
Hmmmm, it seems the .find works differently.

I can search with arr[0].find(x) or if I want to search the next dimension with arr[1].find(y)
TomToad
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Posted: 20th Nov 2018 17:41
.find() only works for sorted arrays. For unsorted, you will need to use a for loop and check each item of the array.

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