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DLL Talk / QUESTION ABOUT THE colorDialog() COMMAND IN BLUE GUI

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Suzaku
19
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Joined: 1st Dec 2004
Location: I have no idea
Posted: 14th Feb 2005 01:47
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Quote: "Return Value:
The colour which the user picked. This colour is the same format as the colour which the RGB() function returns."




That is what i have so far, but how can I use the colorDialog() command to return the red value as a, the green value as b, and the blue value as c?
I already tried something like
Quote: "
a,b,c=colorDialog()
or
colorDialog(a,b,c)
"


What am I doing wrong?
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the_winch
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Location: Oxford, UK
Posted: 14th Feb 2005 02:39
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Get the colour value back from colorDialog() then use RGBR(), RGBG() and RGBB() to split the colour value into seperate variables.

Quote: "this is not a quote"
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Suzaku
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Posted: 14th Feb 2005 07:27
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Well I'm not sure i know how but I'll try!
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Suzaku
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Posted: 14th Feb 2005 07:34
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Can someone please give me an example of what the_winch means when he says
Quote: "Get the colour value back from colorDialog() then use RGBR(), RGBG() and RGBB() to split the colour value into seperate variables."
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Suzaku
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Posted: 14th Feb 2005 07:38
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Nevermind, I figured it out.

Thanks for the help the_winch!
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