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DarkBASIC Discussion / RGB Function

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hexGEAR
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Posted: 9th Mar 2004 21:56 Edited at: 9th Mar 2004 21:57
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Could someone briefly explain how the RGB funciton works i quickly scanned the internet but didn't find anything reasonable. So basically how do these two equate?

rgb(255,255,255) = 4,294,967,295

thanks

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zircher
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Posted: 9th Mar 2004 22:47
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Ok, a byte (8 bits) can range from 0 to 255.

A number stored in binary does the ol' power of two thing.

So, 255,255,255 becomes FF,FF,FF in hex or binary
11111111, 11111111, 1111111.

11111111111111111111111 is a very big number in binary.
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TAZ

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hexGEAR
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Posted: 10th Mar 2004 00:05 Edited at: 10th Mar 2004 00:14
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Quote: "11111111111111111111111 is a very big number in binary"


but not quite big enough unless my math is rusty i'd say the decimal equivalent of the binary above is "16,777,215" (same for FF FF FF in hex i guess) which is still pretty far from "4,294,967,295"

dunno, i might be wrong though

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hexGEAR
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Posted: 10th Mar 2004 00:37
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it's about 33 1's in a row:

11111111 11111111 11111111 11111111 1

if the first set of 8 bits if for red, the next for green and the last for blue then how about the final 9 bits?

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zircher
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Posted: 10th Mar 2004 00:59
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Ah, the alpha channel for 32 bit colors, basically the transparency setting.
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hexGEAR
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Posted: 10th Mar 2004 01:09 Edited at: 10th Mar 2004 01:21
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cool

[edit]

anyone else interested, manual calculation of the RGB value is:

rgbVal = blue + (green*256) + (red*65536) + alpha

where the alpha is 4278190080, the last 9 bits:

(2^32)+(2^31)+(2^30)+(2^29)+(2^28)+(2^27)+(2^26)+(2^25)+(2^24)

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