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DarkBASIC Discussion / I THINK IM GOING CRAZY

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21
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Joined: 30th Oct 2003
Location: BALTIMORE,MARYLAND
Posted: 16th Mar 2004 04:56
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HOW CAN AN ARRAY BE ACCESSED OUT OF BOUNDS WHEN FUNCTIONS USE VALUES TO GAIN ACCESS TO THEM WHEN THEY ARE GLOBAL?

FUNCTION VECTOR_CROSS_PRODUCT(VECTORW#,VECTORU#,VECTORV#)
U=INT(VECTORU#)
V=INT(VECTORV#)
W=INT(VECTORW#)
X=0
Y=1
Z=2

VECTOR#(W,X)= (VECTOR#(U,Y)*VECTOR#(V,Z))-(VECTOR#(U,Z)*VECTOR#(V,Y))
VECTOR#(W,Y)=(-1.0*VECTOR#(U,X)*VECTOR#(V,Z))+(VECTOR#(U,Z)*VECTOR#(V,X))
VECTOR#(W,Z)= (VECTOR#(U,X)*VECTOR#(V,Y))-(VECTOR#(U,Y)*VECTOR#(V,X))
ENDFUNCTION
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John Y
Synergy Editor Developer
22
Years of Service
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Joined: 4th Sep 2002
Location: UK
Posted: 16th Mar 2004 10:30
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out of bounds means that you have tried to get an index out of an array that doesn't exist, not that it is out of bounds as in your not allowed to access it.

Your probably doing something like this:

Dim myArray(10)

myArray(15) = 20

This is called out of bounds because the array 'myArray' only has 10 places 0,1,2,3,4,5,6,7,8,9 and so there is no place to put the value 20 into position 15

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21
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Joined: 30th Oct 2003
Location: BALTIMORE,MARYLAND
Posted: 16th Mar 2004 17:06
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i understand what you are saying but the array isnt out of bounds. its just a bug. if you look at my code carefully, whats going on is a global dimension is created to hold vectors like this dim
vector#(1,3). then a value is stored like this vector#(0)=0.0 and is passed into the function to know what vector# to access. its a bug.
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