any one no the answer tell me NOW (distances)

Author

Message

AlexI

20

Years of Service

User Offline

Joined: 31st Dec 2004

Location: UK

Posted: 19th Mar 2005 05:59

Link

+ Code Snippet

IF (objx1#-objx2#)^2 + (objy1#-objy2#)^2 + (objz1#-objz2#)^2 < 100(for distace)^2 then end

wherer do i enter the distance in this code

Back to top

Profile PM

Mr Pointless

20

Years of Service

User Offline

Joined: 17th Oct 2004

Location: Stuck in the UK

Posted: 19th Mar 2005 06:05

Link

If I knew what it was for, I might be able to figure it out, but since you put just that line, it doesn't make sense. To me at least.

Iwata: "YOU'RE NOT HIM! YOU'RE NOT SUMIYOSHI! EEEEYAAAAAA!"
Sumiyoshi: "Who am I then?

Back to top

Profile PM Email

BearCDPOLD

21

Years of Service

User Offline

Joined: 16th Oct 2003

Location: AZ,USA

Posted: 19th Mar 2005 06:47

Link

To quote Joe Coonig:

Quote: "s Nosnevel Xela didn't finish. sqrt((x1-x2)^2+(z1-z2)^2)=distance where x1,z1 is locationof starting object and x2,z2 is the coordinates of ending object. To find it in 3d, make it sqrt((x1-x2)^2+(y1-y2)^2+(z1-z2)^2)=distance where y1 and y2 are the y positions for the start and end."

Crazy Donut Productions
Current Project: A Redneck game

Back to top

Profile PM Email Website

AlexI

20

Years of Service

User Offline

Joined: 31st Dec 2004

Location: UK

Posted: 19th Mar 2005 16:51

Link

[/code]wheres do you enter the distance on this code for it to go on to the "then"
[code]
IF (objx1#-objx2#)^2 + (objy1#-objy2#)^2 + (objz1#-objz2#)^2 < 100(for distace)^2 then end

@ Bear Crazy Donut Productions to confusing

Back to top

Profile PM

Mobiius

Valued Member

22

Years of Service

User Offline

Joined: 27th Feb 2003

Location: The Cold North

Posted: 19th Mar 2005 19:33 Edited at: 19th Mar 2005 19:37

Link

+ Code Snippet

Object01_X# = Object Position X(ObjectId):` Gets Object01s X Position
Object01_Y# = Object Position Y(ObjectId):` Gets Object01s Y Position
Object01_Z# = Object Position Z(ObjectId):` Gets Object01s Z Position


Object02_X# = Object Position X(ObjectId):` Gets Object02s X Position
Object02_Y# = Object Position Y(ObjectId):` Gets Object02s Y Position
Object02_Z# = Object Position Z(ObjectId):` Gets Object02s Z Position


Dist_X# = Object01_X# - Object02_X#:` Gets The X Distance From Object01s Start Position To Object02s Position
Dist_Y# = Object01_Y# - Object02_Y#:` Gets The Y Distance From Object01s Start Position To Object02s Position
Dist_Z# = Object01_Z# - Object02_Z#:` Gets The Z Distance From Object01s Start Position To Its Object02s Position


`Gets The Actual Distance From The Actors Start Position To Its Current Position
Distance# = Sqrt(Dist_X# * Dist_X# + Dist_Y# * Dist_Y# + Dist_Z# * Dist_Z#)

Just change the ObjectID variable to reflect the 2 objects numbers and the answer is in Distance#

*EDIT* Remember, there is two sets of commands to get object positions, the first 3 are object 1, the second 3 are object 2. Infact, have this.

+ Code Snippet

Function GetDistance#(Obj01, Obj02)
   Object01_X# = Object Position X(Obj01):` Gets Object01s X Position
   Object01_Y# = Object Position Y(Obj01):` Gets Object01s Y Position
   Object01_Z# = Object Position Z(Obj01):` Gets Object01s Z Position


   Object02_X# = Object Position X(Obj02):` Gets Object02s X Position
   Object02_Y# = Object Position Y(Obj02):` Gets Object02s Y Position
   Object02_Z# = Object Position Z(Obj02):` Gets Object02s Z Position


   Dist_X# = Object01_X# - Object02_X#:` Gets The X Distance From Object01s Start Position To Object02s Position
   Dist_Y# = Object01_Y# - Object02_Y#:` Gets The Y Distance From Object01s Start Position To Object02s Position
   Dist_Z# = Object01_Z# - Object02_Z#:` Gets The Z Distance From Object01s Start Position To Its Object02s Position


   `Gets The Actual Distance From The Actors Start Position To Its Current Position
   Distance# = Sqrt(Dist_X# * Dist_X# + Dist_Y# * Dist_Y# + Dist_Z# * Dist_Z#)
EndFunction Distance#

Just call GetDistance#(Object Number 1, Object Number 2) and it gives you the distance.

1800+ XP - GeforceFX 5600 - 256MbDDR - 60Gb Hdd - XP Pro (SP2)

Back to top

Profile PM Email Website

Baggers

20

Years of Service

User Offline

Joined: 31st May 2004

Location: Yonder over dem dere hills

Posted: 19th Mar 2005 21:17

Link

!Hi! although Mobiius has answered you question i would just request that as a matter of etiquette on these forums that you dont make such demanding threads, a please and a thankyou can go along way.

Back to top

Profile PM Email

Fud

20

Years of Service

User Offline

Joined: 16th Nov 2004

Location: