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DarkBASIC Discussion / Math Question

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Blazer
22
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Joined: 22nd Oct 2002
Location: United States
Posted: 2nd May 2003 04:21 Edited at: 2nd May 2003 04:24
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I learned in Math the other day that you can draw a circle with this equation:

(X-H)^2+(Y-K)^2<R^2

(darn my post got deleted)

so I plugged it in DB like this:

(object position x(1)-(a point))^2-(object position y(1)-(a point))^2<R^2

but it didn't work...... can somone tell me how to cheack if something is within a cirle

ps: yes I do listen in Math class

As I walk through the vally of the shadow of death, I will fear no evil.
- Psalms 23:4
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hexGEAR
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Joined: 3rd Nov 2002
Location: Naytonia
Posted: 2nd May 2003 04:43
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you talkin 2D or 3D? if 3D the using the mathematical distance formula to detect if something is in range is the same thing as checking if something is within a circular perimeter of the target!

dist = sqrt( (x1-x2)^2 + (y1-y2)^2 + (z1-z2)^2 )

for 2D it would kinda be the same thing withought the z part to represent the 3rd dimension.

everyday of life is a new chapter that has already been fortold but is up to the soul to capture.
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AsriCE
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Joined: 10th Jan 2003
Location: Brunei
Posted: 2nd May 2003 05:11
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You can try using trigonometry to make circles. The following snippet is using 2D, but you can modify it easily to for your own use.



Asri CE Crew

Anak Brunei!
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Hell IVIonkey
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Joined: 1st Apr 2003
Location: Outer Limits
Posted: 2nd May 2003 06:34 Edited at: 2nd May 2003 08:30
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oh boy... variables can only be assigned in ANY programming language by the form of [variable] = [expression] (unless you use something like inc [variable] or [variable]++).

To draw a circle, use AsriCE's method if you need to do it mathematically; otherwise use the DB function.


EDIT: Hmm think I read this wrong; were you just trying to do a test instead of assigning a variable? In that case, your problem is that you used a "-" sign between squared terms instead of a "+".
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